If the page size is 8 KB, how many bits are required for the page offset?

Options

  • A. 10 bits
  • B. 12 bits
  • C. 13 bits
  • D. More than one of the above
  • E. None of the above

Correct Answer (Detailed Explanation is Below)

C. 13 bits

Detailed Explanation

8 KB equals 8192 bytes, which is 2^13 bytes. Therefore, 13 bits are required for the page offset.