The speed of an electron in the third Bohr orbit of hydrogen is approximately
Options
- A. c/137
- B. c/274
- C. c/411
- D. 3c/137
- E. None of the above
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Correct Answer (Detailed Explanation is Below)
C. c/411
Detailed Explanation
Using v_n = c/(137n), for n = 3 the speed is c/(137 × 3) = c/411.
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