What will be the output of the following C program?

int a[5] = {1,2};
printf("%d", a[3]);

Options

Correct Answer: 0

When an array is partially initialized in C, the elements for which no value is explicitly provided are automatically initialized to 0.

Therefore:

a[0] = 1
a[1] = 2
a[2] = 0
a[3] = 0
a[4] = 0

Hence a[3] is 0.

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