If int a[10] is declared and an int occupies 4 bytes, what is the total size of array a?

Options

C. 40 bytes

Answer: (C) 40 bytes

The total memory required by an array is:

Number of elements × size of each element

Here:

Number of elements = 10

Size of each int = 4 bytes

Therefore:

10 × 4 = 40 bytes

So the array occupies 40 bytes under the size assumption given in the question.

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