What is the output of the following C++ program?
#include <iostream>
using namespace std;
class Base {
public:
virtual void show() {
cout << "Base";
}
};
class Derived : public Base {
public:
void show() override {
cout << "Derived";
}
};
int main() {
Derived d;
Base* p = &d;
p->show();
return 0;
}
Options
-
A.
Base
-
B.
Derived
-
C.
Compilation error
-
D.
More than one of the above
-
E.
None of the above
Correct Answer (Detailed Explanation is Below)
B.
Derived
Detailed Explanation
Correct Answer: Option BExplanation:Because show() is virtual, the call is resolved according to the actual object type at runtime. The base pointer points to a Derived object, so Derived::show() executes and prints
Derived.
