What is the output of the following C++ code?

#include <iostream>
using namespace std;
int fun(int n)
{
    if (n <= 1)
        return n;
    return fun(n - 1) + fun(n - 2);
}
int main()
{
    cout << fun(5);
    return 0;
}
                        

Options

  • A. 3
  • B. 5
  • C. 8
  • D. More than one of the above
  • E. None of the above

Correct Answer (Detailed Explanation is Below)

B. 5

Detailed Explanation

Correct Answer: Option B

Explanation:
This is a recursive Fibonacci function. The base cases are fun(0) = 0 and fun(1) = 1. Therefore, fun(2) = 1, fun(3) = 2, fun(4) = 3, and fun(5) = 5.